3.6.83 \(\int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx\) [583]

3.6.83.1 Optimal result
3.6.83.2 Mathematica [A] (verified)
3.6.83.3 Rubi [A] (verified)
3.6.83.4 Maple [B] (verified)
3.6.83.5 Fricas [B] (verification not implemented)
3.6.83.6 Sympy [F(-1)]
3.6.83.7 Maxima [A] (verification not implemented)
3.6.83.8 Giac [F]
3.6.83.9 Mupad [F(-1)]

3.6.83.1 Optimal result

Integrand size = 33, antiderivative size = 421 \[ \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx=\frac {\left (3 a^2 b (A-B)-b^3 (A-B)+a^3 (A+B)-3 a b^2 (A+B)\right ) \arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} d}-\frac {\left (3 a^2 b (A-B)-b^3 (A-B)+a^3 (A+B)-3 a b^2 (A+B)\right ) \arctan \left (1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} d}+\frac {2 \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right ) \sqrt {\cot (c+d x)}}{d}+\frac {2 a \left (7 a^2 A-18 A b^2-21 a b B\right ) \cot ^{\frac {3}{2}}(c+d x)}{21 d}-\frac {2 a^2 (11 A b+7 a B) \cot ^{\frac {5}{2}}(c+d x)}{35 d}-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (b+a \cot (c+d x))^2}{7 d}-\frac {\left (a^3 (A-B)-3 a b^2 (A-B)-3 a^2 b (A+B)+b^3 (A+B)\right ) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{2 \sqrt {2} d}+\frac {\left (a^3 (A-B)-3 a b^2 (A-B)-3 a^2 b (A+B)+b^3 (A+B)\right ) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{2 \sqrt {2} d} \]

output
2/21*a*(7*A*a^2-18*A*b^2-21*B*a*b)*cot(d*x+c)^(3/2)/d-2/35*a^2*(11*A*b+7*B 
*a)*cot(d*x+c)^(5/2)/d-2/7*a*A*cot(d*x+c)^(3/2)*(b+a*cot(d*x+c))^2/d-1/2*( 
3*a^2*b*(A-B)-b^3*(A-B)+a^3*(A+B)-3*a*b^2*(A+B))*arctan(-1+2^(1/2)*cot(d*x 
+c)^(1/2))/d*2^(1/2)-1/2*(3*a^2*b*(A-B)-b^3*(A-B)+a^3*(A+B)-3*a*b^2*(A+B)) 
*arctan(1+2^(1/2)*cot(d*x+c)^(1/2))/d*2^(1/2)-1/4*(a^3*(A-B)-3*a*b^2*(A-B) 
-3*a^2*b*(A+B)+b^3*(A+B))*ln(1+cot(d*x+c)-2^(1/2)*cot(d*x+c)^(1/2))/d*2^(1 
/2)+1/4*(a^3*(A-B)-3*a*b^2*(A-B)-3*a^2*b*(A+B)+b^3*(A+B))*ln(1+cot(d*x+c)+ 
2^(1/2)*cot(d*x+c)^(1/2))/d*2^(1/2)+2*(3*A*a^2*b-A*b^3+B*a^3-3*B*a*b^2)*co 
t(d*x+c)^(1/2)/d
 
3.6.83.2 Mathematica [A] (verified)

Time = 3.91 (sec) , antiderivative size = 326, normalized size of antiderivative = 0.77 \[ \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx=\frac {2 \sqrt {\cot (c+d x)} \left (-\frac {\left (3 a^2 b (A-B)+b^3 (-A+B)+a^3 (A+B)-3 a b^2 (A+B)\right ) \left (\arctan \left (1-\sqrt {2} \sqrt {\tan (c+d x)}\right )-\arctan \left (1+\sqrt {2} \sqrt {\tan (c+d x)}\right )\right )}{2 \sqrt {2}}-\frac {\left (a^3 (A-B)+3 a b^2 (-A+B)-3 a^2 b (A+B)+b^3 (A+B)\right ) \left (\log \left (1-\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )-\log \left (1+\sqrt {2} \sqrt {\tan (c+d x)}+\tan (c+d x)\right )\right )}{4 \sqrt {2}}-\frac {a^3 A}{7 \tan ^{\frac {7}{2}}(c+d x)}-\frac {a^2 (3 A b+a B)}{5 \tan ^{\frac {5}{2}}(c+d x)}+\frac {a \left (a^2 A-3 A b^2-3 a b B\right )}{3 \tan ^{\frac {3}{2}}(c+d x)}+\frac {3 a^2 A b-A b^3+a^3 B-3 a b^2 B}{\sqrt {\tan (c+d x)}}\right ) \sqrt {\tan (c+d x)}}{d} \]

input
Integrate[Cot[c + d*x]^(9/2)*(a + b*Tan[c + d*x])^3*(A + B*Tan[c + d*x]),x 
]
 
output
(2*Sqrt[Cot[c + d*x]]*(-1/2*((3*a^2*b*(A - B) + b^3*(-A + B) + a^3*(A + B) 
 - 3*a*b^2*(A + B))*(ArcTan[1 - Sqrt[2]*Sqrt[Tan[c + d*x]]] - ArcTan[1 + S 
qrt[2]*Sqrt[Tan[c + d*x]]]))/Sqrt[2] - ((a^3*(A - B) + 3*a*b^2*(-A + B) - 
3*a^2*b*(A + B) + b^3*(A + B))*(Log[1 - Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c 
 + d*x]] - Log[1 + Sqrt[2]*Sqrt[Tan[c + d*x]] + Tan[c + d*x]]))/(4*Sqrt[2] 
) - (a^3*A)/(7*Tan[c + d*x]^(7/2)) - (a^2*(3*A*b + a*B))/(5*Tan[c + d*x]^( 
5/2)) + (a*(a^2*A - 3*A*b^2 - 3*a*b*B))/(3*Tan[c + d*x]^(3/2)) + (3*a^2*A* 
b - A*b^3 + a^3*B - 3*a*b^2*B)/Sqrt[Tan[c + d*x]])*Sqrt[Tan[c + d*x]])/d
 
3.6.83.3 Rubi [A] (verified)

Time = 1.59 (sec) , antiderivative size = 355, normalized size of antiderivative = 0.84, number of steps used = 24, number of rules used = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.697, Rules used = {3042, 4064, 3042, 4090, 27, 3042, 4120, 27, 3042, 4113, 3042, 4011, 3042, 4017, 27, 1482, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \cot (c+d x)^{9/2} (a+b \tan (c+d x))^3 (A+B \tan (c+d x))dx\)

\(\Big \downarrow \) 4064

\(\displaystyle \int \sqrt {\cot (c+d x)} (a \cot (c+d x)+b)^3 (A \cot (c+d x)+B)dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )^3 \left (B-A \tan \left (c+d x+\frac {\pi }{2}\right )\right )dx\)

\(\Big \downarrow \) 4090

\(\displaystyle -\frac {2}{7} \int \frac {1}{2} \sqrt {\cot (c+d x)} (b+a \cot (c+d x)) \left (-a (11 A b+7 a B) \cot ^2(c+d x)+7 \left (A a^2-2 b B a-A b^2\right ) \cot (c+d x)+b (3 a A-7 b B)\right )dx-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {1}{7} \int \sqrt {\cot (c+d x)} (b+a \cot (c+d x)) \left (-a (11 A b+7 a B) \cot ^2(c+d x)+7 \left (A a^2-2 b B a-A b^2\right ) \cot (c+d x)+b (3 a A-7 b B)\right )dx-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {1}{7} \int \sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (b-a \tan \left (c+d x+\frac {\pi }{2}\right )\right ) \left (-a (11 A b+7 a B) \tan \left (c+d x+\frac {\pi }{2}\right )^2-7 \left (A a^2-2 b B a-A b^2\right ) \tan \left (c+d x+\frac {\pi }{2}\right )+b (3 a A-7 b B)\right )dx-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 4120

\(\displaystyle \frac {1}{7} \left (-\frac {2}{5} \int \frac {5}{2} \sqrt {\cot (c+d x)} \left ((3 a A-7 b B) b^2+a \left (7 A a^2-21 b B a-18 A b^2\right ) \cot ^2(c+d x)+7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3\right ) \cot (c+d x)\right )dx-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{7} \left (-\int \sqrt {\cot (c+d x)} \left ((3 a A-7 b B) b^2+a \left (7 A a^2-21 b B a-18 A b^2\right ) \cot ^2(c+d x)+7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3\right ) \cot (c+d x)\right )dx-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{7} \left (-\int \sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left ((3 a A-7 b B) b^2+a \left (7 A a^2-21 b B a-18 A b^2\right ) \tan \left (c+d x+\frac {\pi }{2}\right )^2-7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3\right ) \tan \left (c+d x+\frac {\pi }{2}\right )\right )dx-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 4113

\(\displaystyle \frac {1}{7} \left (-\int \sqrt {\cot (c+d x)} \left (7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3\right ) \cot (c+d x)-7 \left (A a^3-3 b B a^2-3 A b^2 a+b^3 B\right )\right )dx+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{7} \left (-\int \sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )} \left (-7 \left (A a^3-3 b B a^2-3 A b^2 a+b^3 B\right )-7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3\right ) \tan \left (c+d x+\frac {\pi }{2}\right )\right )dx+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 4011

\(\displaystyle \frac {1}{7} \left (-\int \frac {-7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3\right )-7 \left (A a^3-3 b B a^2-3 A b^2 a+b^3 B\right ) \cot (c+d x)}{\sqrt {\cot (c+d x)}}dx+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{7} \left (-\int \frac {7 \left (A a^3-3 b B a^2-3 A b^2 a+b^3 B\right ) \tan \left (c+d x+\frac {\pi }{2}\right )-7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3\right )}{\sqrt {-\tan \left (c+d x+\frac {\pi }{2}\right )}}dx+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 4017

\(\displaystyle \frac {1}{7} \left (-\frac {2 \int \frac {7 \left (B a^3+3 A b a^2-3 b^2 B a-A b^3+\left (A a^3-3 b B a^2-3 A b^2 a+b^3 B\right ) \cot (c+d x)\right )}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{7} \left (-\frac {14 \int \frac {B a^3+3 A b a^2-3 b^2 B a-A b^3+\left (A a^3-3 b B a^2-3 A b^2 a+b^3 B\right ) \cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 1482

\(\displaystyle \frac {1}{7} \left (-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \int \frac {\cot (c+d x)+1}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}\right )}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 1476

\(\displaystyle \frac {1}{7} \left (-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \left (\frac {1}{2} \int \frac {1}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}+\frac {1}{2} \int \frac {1}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}\right )-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}\right )}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {1}{7} \left (-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \left (\frac {\int \frac {1}{-\cot (c+d x)-1}d\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\cot (c+d x)-1}d\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}\right )-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}\right )}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {1}{7} \left (-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \int \frac {1-\cot (c+d x)}{\cot ^2(c+d x)+1}d\sqrt {\cot (c+d x)}\right )}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 1479

\(\displaystyle \frac {1}{7} \left (-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \left (-\frac {\int -\frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}\right )\right )}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {1}{7} \left (-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}\right )\right )}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{7} \left (-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \left (\frac {\int \frac {\sqrt {2}-2 \sqrt {\cot (c+d x)}}{\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}}{2 \sqrt {2}}+\frac {1}{2} \int \frac {\sqrt {2} \sqrt {\cot (c+d x)}+1}{\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1}d\sqrt {\cot (c+d x)}\right )\right )}{d}+\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {1}{7} \left (\frac {2 a \left (7 a^2 A-21 a b B-18 A b^2\right ) \cot ^{\frac {3}{2}}(c+d x)}{3 d}-\frac {2 a^2 (7 a B+11 A b) \cot ^{\frac {5}{2}}(c+d x)}{5 d}-\frac {14 \left (\frac {1}{2} \left (a^3 (A+B)+3 a^2 b (A-B)-3 a b^2 (A+B)-b^3 (A-B)\right ) \left (\frac {\arctan \left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2}}\right )-\frac {1}{2} \left (a^3 (A-B)-3 a^2 b (A+B)-3 a b^2 (A-B)+b^3 (A+B)\right ) \left (\frac {\log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{2 \sqrt {2}}\right )\right )}{d}+\frac {14 \left (a^3 B+3 a^2 A b-3 a b^2 B-A b^3\right ) \sqrt {\cot (c+d x)}}{d}\right )-\frac {2 a A \cot ^{\frac {3}{2}}(c+d x) (a \cot (c+d x)+b)^2}{7 d}\)

input
Int[Cot[c + d*x]^(9/2)*(a + b*Tan[c + d*x])^3*(A + B*Tan[c + d*x]),x]
 
output
(-2*a*A*Cot[c + d*x]^(3/2)*(b + a*Cot[c + d*x])^2)/(7*d) + ((14*(3*a^2*A*b 
 - A*b^3 + a^3*B - 3*a*b^2*B)*Sqrt[Cot[c + d*x]])/d + (2*a*(7*a^2*A - 18*A 
*b^2 - 21*a*b*B)*Cot[c + d*x]^(3/2))/(3*d) - (2*a^2*(11*A*b + 7*a*B)*Cot[c 
 + d*x]^(5/2))/(5*d) - (14*(((3*a^2*b*(A - B) - b^3*(A - B) + a^3*(A + B) 
- 3*a*b^2*(A + B))*(-(ArcTan[1 - Sqrt[2]*Sqrt[Cot[c + d*x]]]/Sqrt[2]) + Ar 
cTan[1 + Sqrt[2]*Sqrt[Cot[c + d*x]]]/Sqrt[2]))/2 - ((a^3*(A - B) - 3*a*b^2 
*(A - B) - 3*a^2*b*(A + B) + b^3*(A + B))*(-1/2*Log[1 - Sqrt[2]*Sqrt[Cot[c 
 + d*x]] + Cot[c + d*x]]/Sqrt[2] + Log[1 + Sqrt[2]*Sqrt[Cot[c + d*x]] + Co 
t[c + d*x]]/(2*Sqrt[2])))/2))/d)/7
 

3.6.83.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 1482
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
a*c, 2]}, Simp[(d*q + a*e)/(2*a*c)   Int[(q + c*x^2)/(a + c*x^4), x], x] + 
Simp[(d*q - a*e)/(2*a*c)   Int[(q - c*x^2)/(a + c*x^4), x], x]] /; FreeQ[{a 
, c, d, e}, x] && NeQ[c*d^2 + a*e^2, 0] && NeQ[c*d^2 - a*e^2, 0] && NegQ[(- 
a)*c]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4011
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)]), x_Symbol] :> Simp[d*((a + b*Tan[e + f*x])^m/(f*m)), x] + Int 
[(a + b*Tan[e + f*x])^(m - 1)*Simp[a*c - b*d + (b*c + a*d)*Tan[e + f*x], x] 
, x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 
 0] && GtQ[m, 0]
 

rule 4017
Int[((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])/Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_ 
)]], x_Symbol] :> Simp[2/f   Subst[Int[(b*c + d*x^2)/(b^2 + x^4), x], x, Sq 
rt[b*Tan[e + f*x]]], x] /; FreeQ[{b, c, d, e, f}, x] && NeQ[c^2 - d^2, 0] & 
& NeQ[c^2 + d^2, 0]
 

rule 4064
Int[(cot[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_.) + (b_.)*tan[(e_.) + (f_.)*( 
x_)])^(m_.)*((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Simp 
[g^(m + n)   Int[(g*Cot[e + f*x])^(p - m - n)*(b + a*Cot[e + f*x])^m*(d + c 
*Cot[e + f*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] &&  !Integer 
Q[p] && IntegerQ[m] && IntegerQ[n]
 

rule 4090
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*tan[(e_.) + 
 (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Si 
mp[b*B*(a + b*Tan[e + f*x])^(m - 1)*((c + d*Tan[e + f*x])^(n + 1)/(d*f*(m + 
 n))), x] + Simp[1/(d*(m + n))   Int[(a + b*Tan[e + f*x])^(m - 2)*(c + d*Ta 
n[e + f*x])^n*Simp[a^2*A*d*(m + n) - b*B*(b*c*(m - 1) + a*d*(n + 1)) + d*(m 
 + n)*(2*a*A*b + B*(a^2 - b^2))*Tan[e + f*x] - (b*B*(b*c - a*d)*(m - 1) - b 
*(A*b + a*B)*d*(m + n))*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, 
 f, A, B, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2 
, 0] && GtQ[m, 1] && (IntegerQ[m] || IntegersQ[2*m, 2*n]) &&  !(IGtQ[n, 1] 
&& ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4113
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*tan[(e_.) 
+ (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[C*((a + 
 b*Tan[e + f*x])^(m + 1)/(b*f*(m + 1))), x] + Int[(a + b*Tan[e + f*x])^m*Si 
mp[A - C + B*Tan[e + f*x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] && 
NeQ[A*b^2 - a*b*B + a^2*C, 0] &&  !LeQ[m, -1]
 

rule 4120
Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.) 
*(x_)])^(n_.)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (f 
_.)*(x_)]^2), x_Symbol] :> Simp[b*C*Tan[e + f*x]*((c + d*Tan[e + f*x])^(n + 
 1)/(d*f*(n + 2))), x] - Simp[1/(d*(n + 2))   Int[(c + d*Tan[e + f*x])^n*Si 
mp[b*c*C - a*A*d*(n + 2) - (A*b + a*B - b*C)*d*(n + 2)*Tan[e + f*x] - (a*C* 
d*(n + 2) - b*(c*C - B*d*(n + 2)))*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, 
b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[c^2 + d^2, 0] && 
  !LtQ[n, -1]
 
3.6.83.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(1191\) vs. \(2(379)=758\).

Time = 1.18 (sec) , antiderivative size = 1192, normalized size of antiderivative = 2.83

method result size
derivativedivides \(\text {Expression too large to display}\) \(1192\)
default \(\text {Expression too large to display}\) \(1192\)

input
int(cot(d*x+c)^(9/2)*(a+b*tan(d*x+c))^3*(A+B*tan(d*x+c)),x,method=_RETURNV 
ERBOSE)
 
output
1/420/d*(1/tan(d*x+c))^(9/2)*tan(d*x+c)*(-840*A*tan(d*x+c)^3*b^3-168*B*tan 
(d*x+c)*a^3-630*B*arctan(1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2)*tan(d*x+c)^(7 
/2)*a*b^2-630*B*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2)*tan(d*x+c)^(7/ 
2)*a^2*b-630*B*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2)*tan(d*x+c)^(7/2 
)*a*b^2-315*B*ln(-(2^(1/2)*tan(d*x+c)^(1/2)-tan(d*x+c)-1)/(1+2^(1/2)*tan(d 
*x+c)^(1/2)+tan(d*x+c)))*2^(1/2)*tan(d*x+c)^(7/2)*a*b^2-315*A*ln(-(1+2^(1/ 
2)*tan(d*x+c)^(1/2)+tan(d*x+c))/(2^(1/2)*tan(d*x+c)^(1/2)-tan(d*x+c)-1))*2 
^(1/2)*tan(d*x+c)^(7/2)*a*b^2+630*A*arctan(1+2^(1/2)*tan(d*x+c)^(1/2))*2^( 
1/2)*tan(d*x+c)^(7/2)*a^2*b-630*A*arctan(1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/ 
2)*tan(d*x+c)^(7/2)*a*b^2+630*A*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2 
)*tan(d*x+c)^(7/2)*a^2*b-630*A*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2) 
*tan(d*x+c)^(7/2)*a*b^2+315*A*ln(-(2^(1/2)*tan(d*x+c)^(1/2)-tan(d*x+c)-1)/ 
(1+2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c)))*2^(1/2)*tan(d*x+c)^(7/2)*a^2*b-31 
5*B*ln(-(1+2^(1/2)*tan(d*x+c)^(1/2)+tan(d*x+c))/(2^(1/2)*tan(d*x+c)^(1/2)- 
tan(d*x+c)-1))*2^(1/2)*tan(d*x+c)^(7/2)*a^2*b-630*B*arctan(1+2^(1/2)*tan(d 
*x+c)^(1/2))*2^(1/2)*tan(d*x+c)^(7/2)*a^2*b+2520*A*tan(d*x+c)^3*a^2*b-120* 
A*a^3-2520*B*tan(d*x+c)^3*a*b^2-840*A*tan(d*x+c)^2*a*b^2-840*B*tan(d*x+c)^ 
2*a^2*b-504*A*tan(d*x+c)*a^2*b+840*B*tan(d*x+c)^3*a^3+280*A*tan(d*x+c)^2*a 
^3+210*A*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2)*tan(d*x+c)^(7/2)*a^3- 
210*A*arctan(-1+2^(1/2)*tan(d*x+c)^(1/2))*2^(1/2)*tan(d*x+c)^(7/2)*b^3-...
 
3.6.83.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 6214 vs. \(2 (379) = 758\).

Time = 6.61 (sec) , antiderivative size = 6214, normalized size of antiderivative = 14.76 \[ \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx=\text {Too large to display} \]

input
integrate(cot(d*x+c)^(9/2)*(a+b*tan(d*x+c))^3*(A+B*tan(d*x+c)),x, algorith 
m="fricas")
 
output
Too large to include
 
3.6.83.6 Sympy [F(-1)]

Timed out. \[ \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx=\text {Timed out} \]

input
integrate(cot(d*x+c)**(9/2)*(a+b*tan(d*x+c))**3*(A+B*tan(d*x+c)),x)
 
output
Timed out
 
3.6.83.7 Maxima [A] (verification not implemented)

Time = 0.45 (sec) , antiderivative size = 366, normalized size of antiderivative = 0.87 \[ \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx=-\frac {210 \, \sqrt {2} {\left ({\left (A + B\right )} a^{3} + 3 \, {\left (A - B\right )} a^{2} b - 3 \, {\left (A + B\right )} a b^{2} - {\left (A - B\right )} b^{3}\right )} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) + 210 \, \sqrt {2} {\left ({\left (A + B\right )} a^{3} + 3 \, {\left (A - B\right )} a^{2} b - 3 \, {\left (A + B\right )} a b^{2} - {\left (A - B\right )} b^{3}\right )} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - \frac {2}{\sqrt {\tan \left (d x + c\right )}}\right )}\right ) - 105 \, \sqrt {2} {\left ({\left (A - B\right )} a^{3} - 3 \, {\left (A + B\right )} a^{2} b - 3 \, {\left (A - B\right )} a b^{2} + {\left (A + B\right )} b^{3}\right )} \log \left (\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right ) + 105 \, \sqrt {2} {\left ({\left (A - B\right )} a^{3} - 3 \, {\left (A + B\right )} a^{2} b - 3 \, {\left (A - B\right )} a b^{2} + {\left (A + B\right )} b^{3}\right )} \log \left (-\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right ) + \frac {120 \, A a^{3}}{\tan \left (d x + c\right )^{\frac {7}{2}}} - \frac {840 \, {\left (B a^{3} + 3 \, A a^{2} b - 3 \, B a b^{2} - A b^{3}\right )}}{\sqrt {\tan \left (d x + c\right )}} - \frac {280 \, {\left (A a^{3} - 3 \, B a^{2} b - 3 \, A a b^{2}\right )}}{\tan \left (d x + c\right )^{\frac {3}{2}}} + \frac {168 \, {\left (B a^{3} + 3 \, A a^{2} b\right )}}{\tan \left (d x + c\right )^{\frac {5}{2}}}}{420 \, d} \]

input
integrate(cot(d*x+c)^(9/2)*(a+b*tan(d*x+c))^3*(A+B*tan(d*x+c)),x, algorith 
m="maxima")
 
output
-1/420*(210*sqrt(2)*((A + B)*a^3 + 3*(A - B)*a^2*b - 3*(A + B)*a*b^2 - (A 
- B)*b^3)*arctan(1/2*sqrt(2)*(sqrt(2) + 2/sqrt(tan(d*x + c)))) + 210*sqrt( 
2)*((A + B)*a^3 + 3*(A - B)*a^2*b - 3*(A + B)*a*b^2 - (A - B)*b^3)*arctan( 
-1/2*sqrt(2)*(sqrt(2) - 2/sqrt(tan(d*x + c)))) - 105*sqrt(2)*((A - B)*a^3 
- 3*(A + B)*a^2*b - 3*(A - B)*a*b^2 + (A + B)*b^3)*log(sqrt(2)/sqrt(tan(d* 
x + c)) + 1/tan(d*x + c) + 1) + 105*sqrt(2)*((A - B)*a^3 - 3*(A + B)*a^2*b 
 - 3*(A - B)*a*b^2 + (A + B)*b^3)*log(-sqrt(2)/sqrt(tan(d*x + c)) + 1/tan( 
d*x + c) + 1) + 120*A*a^3/tan(d*x + c)^(7/2) - 840*(B*a^3 + 3*A*a^2*b - 3* 
B*a*b^2 - A*b^3)/sqrt(tan(d*x + c)) - 280*(A*a^3 - 3*B*a^2*b - 3*A*a*b^2)/ 
tan(d*x + c)^(3/2) + 168*(B*a^3 + 3*A*a^2*b)/tan(d*x + c)^(5/2))/d
 
3.6.83.8 Giac [F]

\[ \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx=\int { {\left (B \tan \left (d x + c\right ) + A\right )} {\left (b \tan \left (d x + c\right ) + a\right )}^{3} \cot \left (d x + c\right )^{\frac {9}{2}} \,d x } \]

input
integrate(cot(d*x+c)^(9/2)*(a+b*tan(d*x+c))^3*(A+B*tan(d*x+c)),x, algorith 
m="giac")
 
output
integrate((B*tan(d*x + c) + A)*(b*tan(d*x + c) + a)^3*cot(d*x + c)^(9/2), 
x)
 
3.6.83.9 Mupad [F(-1)]

Timed out. \[ \int \cot ^{\frac {9}{2}}(c+d x) (a+b \tan (c+d x))^3 (A+B \tan (c+d x)) \, dx=\int {\mathrm {cot}\left (c+d\,x\right )}^{9/2}\,\left (A+B\,\mathrm {tan}\left (c+d\,x\right )\right )\,{\left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )}^3 \,d x \]

input
int(cot(c + d*x)^(9/2)*(A + B*tan(c + d*x))*(a + b*tan(c + d*x))^3,x)
 
output
int(cot(c + d*x)^(9/2)*(A + B*tan(c + d*x))*(a + b*tan(c + d*x))^3, x)